# Avocados Number

Learning Objectives

- Use Avogadro's number to convert to moles and vice versa given the number of particles of an element.
- Know the definition of the mole.
- Determine the formula mass of an ionic or molecular compound.
- Determine the percent composition of each element in a compound from the chemical formula.

When objects are very small, it is often inconvenient or inefficient, or even impossible to deal with the objects one at a time. For these reasons, we often deal with very small objects in groups, and have even invented names for various numbers of objects. The most common of these is 'dozen' which refers to 12 objects. We frequently buy objects in groups of 12, like doughnuts or pencils. Even smaller objects such as straight pins or staples are usually sold in boxes of 144, or a dozen dozen. A group of 144 is called a 'gross'.

Since Avogadro's number is 6.022 × 10 23, it only makes sense that the holiday starts at 6:02 a.m. Revelers tell chemistry jokes, blow bubbles of natural gas that they set ablaze, toast with drinks chilled by dry ice and even recite the mole pledge of allegiance.

- Avogadro's number definition, the constant, 6.022 × 1023, representing the number of atoms, molecules, or ions in one mole of a substance. Symbol: N See more.
- The back has a bit about Avogadro’s number, and admits that “there aren’t 6.0221367×10²³ avocados in here, but 5 plus avo’s isn’t bad!” Related This entry was posted in Highlights, Signs of the Times and tagged chemistry, guacamole, math, Tops on August 21, 2005 by Kelson.

This problem of dealing with things that are too small to operate with as single items also occurs in chemistry. Atoms and molecules are too small to see, let alone to count or measure. Chemists needed to select a group of atoms or molecules that would be convenient to operate with.

## Avogadro's Number:Counting Atoms

Owing to their tiny size, atoms and molecules cannot be counted by direct observation. But much as we do when 'counting' beans in a jar, we can estimate the number of particles in a sample of an element or compound if we have some idea of the volume occupied by each particle and the volume of the container. Once this has been done, we know the number of formula units (to use the most general term for any combination of atoms we wish to define) in any arbitrary weight of the substance. The number will of course depend both on the formula of the substance and on the weight of the sample. However, if we consider a weight of substance that is the same as its formula (molecular) weight expressed in grams, we have only one number to know: **Avogadro's number**.

Avogadro's number

Avogadro's number is known to ten significant digits:

[N_A = 6.022141527 times 10^{23}.]

However, you only need to know it to three significant figures:

[N_A approx 6.02 times 10^{23}. label{3.2.1}]

So (6.02 times 10^{23}) of *what*? Well, of anything you like: apples, stars in the sky, burritos. However, the only *practical* use for (N_A) is to have a more convenient way of expressing the huge numbers of the tiny particles such as atoms or molecules that we deal with in chemistry. Avogadro's number is a *collective number*, just like a dozen. Students can think of (6.02 times 10^{23}) as the 'chemist's dozen'.

Before getting into the use of Avogadro's number in problems, take a moment to convince yourself of the reasoning embodied in the following examples.

Things to understand about Avogadro's number

- It is a
*number*, just as is 'dozen', and thus is*dimensionless*. - It is a
*huge*number, far greater in magnitude than we can visualize - Its practical use is limited to counting tiny things like atoms, molecules, 'formula units', electrons, or photons.
- The value of
*N*can be known only to the precision that the number of atoms in a measurable weight of a substance can be estimated. Because large numbers of atoms cannot be counted directly, a variety of ingenious indirect measurements have been made involving such things as Brownian motion and X-ray scattering._{A}

## The Mole: 'A Dozen Eggs and a Mole of Sugar, Please'

The **mole** (symbol: **mol**) is the base unit of amount of substance ('number of substance') in the International System of Units or System International (SI), defined as exactly 6.02214076×10^{23} particles, e.g., atoms, molecules, ions or electrons. The current definition was adopted in November 2018, revising its old definition based on the number of atoms in 12 grams of carbon-12 (^{12}C) (the isotope of carbon with relative atomic mass 12 Daltons by definition).

### Avogadro's Number Fort Collins

It is not obvious why eggs come in dozens rather than 10s or 14s, or why a ream of paper contains 500 sheets rather than 400 or 600. The definition of a mole—that is, the decision to base it on 12 g of carbon-12—is also arbitrary. The important point is that 1 mole of carbon—or of anything else, whether atoms, compact discs, or houses—always has the same number of objects: 6.02 × 10^{23}.

The Mole

*Video **(PageIndex{1})** How big is a mole?*

## Converting Between Number of Atoms to Moles and Vice Versa

We can use Avogadro's number as a conversion factor, or ratio, in dimensional analysis problems. If we are given the number of atoms of an element X, we can convert it into moles of by using the relationship

[text{1 mol X} = 6.022 times 10^{23} text{ X atoms}.]

An example on the use of Avogadro's number as a conversion factor is given below for carbon.

Example (PageIndex{1}): Moles of Carbon

The element carbon exists in two primary forms: graphite and diamond. How many moles of carbon atoms is (4.72 times 10^{24}) atoms of carbon?

**Solution**

Steps for Problem Solving | The element carbon exists in two primary forms: graphite and diamond. How many moles of carbon atoms is (4.72 times 10^{24}) atoms of carbon? |
---|---|

Identify the 'given'information and what the problem is asking you to 'find.' | Given: (4.72 times 10^{24}) C atoms Find: mol C |

List other known quantities | (1, mol = 6.022 times 10^{23}) C atoms |

Prepare a concept map and use the proper conversion factor. | |

Cancel units and calculate. | [4.72 times 10^{24} : cancel{text{C} : ce{atoms}} times frac{1 : text{mol} : ce{C}}{6.02 times 10^{23} : cancel{text{C} : ce{atoms}}} = 7.84 : text{mol} : ce{C} nonumber] |

Think about your result. | The given number of carbon atoms was greater than Avogadro's number,so the number of moles of (ce{C}) atoms is greater than 1 mole. Since Avogadro's number is a measured quantity with three significant figures, the result of the calculation is rounded to three significant figures |

## Formula Mass

One skill needed in future chapters is the ability to determine the mass of the formula of various chemical substances. This quantity is called the formula mass. The **formula mass** is obtained by adding the masses of each individual atom in the formula of the substance. Because a proper formula is electrically neutral (with no net electrons gained or lost), the ions can be considered atoms for the purpose of calculating the formula mass.

Let us start by calculating the formula mass of sodium chloride (NaCl). This formula mass is the sum of the atomic masses of one sodium atom and one chlorine atom, which we find from the periodic table; here, we use the masses to two decimal places:

To two decimal places, the formula mass of NaCl is 58.44 amu.

For covalent substances, the formula represents the numbers and types of atoms composing a single molecule of the substance; therefore, the formula mass may be correctly referred to as a **molecular mass**. Consider chloroform (CHCl_{3}), a covalent compound once used as a surgical anesthetic and now primarily used in the production of tetrafluoroethylene, the building block for the “anti-stick” polymer, Teflon. The molecular formula of chloroform indicates that a single molecule contains one carbon atom, one hydrogen atom, and three chlorine atoms. The average molecular mass of a chloroform molecule is therefore equal to the sum of the average atomic masses of these atoms.

For ionic compounds with polyatomic ions, the sum must include the number and mass of each atom in the formula for the polyatomic ion. as shown in the example below for aluminum sulfate, Al_{2}(SO_{4})_{3}.

Example (PageIndex{2}) Formula Mass for an Ionic Compound

Aluminum sulfate, Al_{2}(SO_{4})_{3}, is an ionic compound that is used in the manufacture of paper and in various water purification processes. What is the formula mass (amu) of this compound?

**Solution**

The formula for this compound indicates it contains Al^{3+} and SO_{4}^{2−} ions combined in a 2:3 ratio. For purposes of computing a formula mass, it is helpful to rewrite the formula in the simpler format, Al_{2}S_{3}O_{12}. Following the approach outlined above, the formula mass for this compound is calculated as follows:

The formula mass for Al_{2}(SO_{4})_{3}, is 342.14 amu.

Exercise (PageIndex{1})

Use the atomic masses (rounded to two decimal places) to determine the formula mass for each ionic compound.

- TiO
_{2} - AgBr
- Au(NO
_{3})_{3} - Fe
_{3}(PO_{4})_{2}

**Answer**

a. 79.87 amu

b. 187.77 amu

### Avogadro's Number Calculator

c. 383.0 amu

## Percent Composition of a Compound from a Chemical Formula

The percent composition of a compound can also be determined from the formula of the compound. The subscripts in the formula are first used to calculate the mass of each element in one mole of the compound. That is divided by the molar mass of the compound and multiplied by (100%).

[% : text{by mass} = frac{text{mass of element in} : 1 : text{mol}}{text{molar mass of compound}} times 100%]

The percent composition of a given compound is always the same as long as the compound is pure.

Example (PageIndex{3})

Dichlorine heptoxide (left( ce{Cl_2O_7} right)) is a highly reactive compound used in some organic synthesis reactions. Calculate the percent composition of dichlorine heptoxide.

**Solution**

Steps for Problem Solving | Calculate the percent composition of dichlorine heptoxide (left( ce{Cl_2O_7} right)). |
---|---|

Identify the 'given'information and what the problem is asking you to 'find.' | Given : Cl Find: % Composition (% Cl and %O) |

List other known quantities | Mass of Cl in 1 mol Cl Mass of O in 1 mol Cl Molar mass of Cl |

Cancel units and calculate. | [% ce{Cl} = frac{70.90 : text{g} : ce{Cl}}{182.90 : text{g}} times 100% = 38.76% : ce{Cl} nonumber] [% : ce{O} = frac{112.00 : text{g} : ce{O}}{182.90 : text{g}} times 100% = 61.24% : ce{O} nonumber] Calculate the percent by mass of each element by dividing the mass of that element in 1 mole of the compound by the molar mass of the compound and multiplying by (100%). |

Think about your result. | The percentages add up to (100%). |

Percent composition can also be used to determine the mass of a certain element that is contained in any mass of a compound. In the previous sample problem, it was found that the percent composition of dichlorine heptoxide is (38.76% : ce{Cl}) and (61.24% : ce{O}). Suppose that you needed to know the masses of chlorine and oxygen present in a (12.50 : text{g}) sample of dichlorine heptoxide. You can set up a conversion factor based on the percent by mass of each element.

[12.50 : text{g} : ce{Cl_2O_7} times frac{38.76 : text{g} : ce{Cl}}{100 : text{g} : ce{Cl_2O_7}} = 4.845 : text{g} : ce{Cl}]

[12.50 : text{g} : ce{Cl_2O_7} times frac{61.24 : text{g} : ce{O}}{100 : text{g} : ce{Cl_2O_7}} = 7.655 : text{g} : ce{O}]

The sum of the two masses is (12.50 : text{g}), the mass of the sample size.

Exercise (PageIndex{2})

Barium fluoride is a transparent crystal that can be found in nature as the mineral frankdicksonite. Determine the percent composition of barium fluoride.

**Answer a:**- 78.32% Ba and 21.67% F

## Summary

- The
**mole**(symbol:**mol**) is the base unit of amount of substance ('number of substance') in the International System of Units or System International (SI), defined as exactly 6.02214076×10^{23}particles, e.g., atoms, molecules, ions or electrons. - Avogadro's number is related to moles of any substance X as follows:

[text{1 mol X} = 6.022 times 10^{23} text{ X atoms}.]

- Formula masses of ionic and molecular compounds can be determined from the masses of the atoms in their formulas.
- Processes are described for calculating the percent composition of a compound based on the chemical formula.

Anonymous

Paul Flowers (University of North Carolina - Pembroke), Klaus Theopold (University of Delaware) and Richard Langley (Stephen F. Austin State University) with contributing authors. Textbook content produced by OpenStax College is licensed under a Creative Commons Attribution License 4.0 license. Download for free at http://cnx.org/contents/[email protected]).

Stephen Lower, Professor Emeritus (Simon Fraser U.) Chem1 Virtual Textbook

Marisa Alviar-Agnew (Sacramento City College)

Henry Agnew (UC Davis)

- Wikipedia

No, no, get a grip, Isabel. It’s *Avogadro’s* number, and I haven’t thought much about it since I first encountered it in high-school Chemistry class, lo, these 50 years ago now. Nor did I know much about it even back in the day.

I never knew, for example, that Avogadro was an Italian lawyer’s last name, or if I did know, it did not stick.

Likewise, I never knew that the number was not determined by Amadeo Avogadro (which sounds much cooler in Italian than in English). No, after Avogadro’s other number came up in 1856, Avogadro’s number as we know it (or as we don’t) was determined by some other guys:

- Josef Loschmidt, an Austrian high-school teacher who is credited as being the first person to estimate the number of particles in a given quantity of matter, in 1865 (presumably the first to estimate this number with precision more exacting than “a whole bunch”)
- Jean Baptiste Perrin, a French physicist who coined the term and reported an estimate of it in 1909 based on his work on Brownian motion, the discovery of which in 1827 by Robert Brown, a Scottish botanist, had demonstrated the active nature of molecules

It’s sort of cool, I think, that this story includes so many nationalities — Italian, Austrian, French, Scottish — and so many unchemical occupations — lawyer, teacher, physicist, botanist. It’s at once largely incomprehensible and amazingly inclusive. And it’s cool that even 50 years after your death someone might name something both fundamental and lasting after you (but not, apparently, 50 years after your high-school graduation).

But what is that something, you ask? For any others who’ve forgotten or never knew their high-school chemistry, here’s Wiki’s take on it:

*The Avogadro constant (N_{A} or L) is the proportionality factor that relates the number of constituent particles (usually molecules, atoms or ions) in a sample with the amount of substance in that sample. Its SI unit is the reciprocal mole, and it is defined as N_{A} = 6.02214076×10^{23} mol^{−1}. . . The numeric value of the Avogadro constant expressed in reciprocal mole, a dimensionless number, is called the Avogadro number, sometimes denoted N or N_{0}, which is thus the number of particles that are contained in one mole, exactly 6.02214076×10^{23}.*

All right then. Not having day-to-day familiarity with proportionality factors or dimensionless numbers, and although I would not heretofore have said that they are a model of accessibility, I even prefer how Scientific American explains it . . .

### Avogadro's Full Number

. . . the number of particles in a unit known as a mole . . .

### Avocado's Number Trader Joe's

although I never actually got that whole(y)/holy mole(y) thing, either.

Really, I prefer-er how William McGuire Bryson explains it . . .

. . . the number of molecules found

in 2.016 grams of hydrogen gas

or an equal volume of any other gas . . .

although I get confused when we jump from units of weight to talk of volume.

Bryson gives the actual Avogadro number (6.0221367 x 10^{23}) (and no, Bryson’s number and Wiki’s do not match and I have no idea why not), and then he notes that it’s a Big Number. But — and here, finally, is the payoff — if you, like me, have little intuitive feel for just How Big once you get past, oh, 10^{3}, Bryson has help.

Chemistry students have long amused themselves

by computing just how large a number it is,

so I can report that it is equivalent

to the number of popcorn kernels*[Ed.’s question: Popped or unpopped kernels?]*

needed to cover the United States to a depth of nine miles*[Ed.’s admission: OK, at 9 miles it likely doesn’t matter.]*,

or cupfuls of water in the Pacific ocean,

or soft drink cans that would, evenly stacked,

cover the Earth to a depth of 200 miles.

An equivalent number of American pennies

would be enough to make every person on Earth

a dollar trillionaire.*[Ed’s question: Are there persons elsewhere?]*

It is a big number.

– A Short History of Nearly Everything

Indeed it is. I don’t know about you, but I was not amusing myself in Chemistry class by doing any of these calculations, although amusement I surely and sorely needed. Where was Bill Bryson then? I don’t know, but I’m glad he’s here now.